School and Work

Sorry, I could not read the content fromt this page.

View the original article here

Home >All Categories > Science & Mathematics >Physics >Open Question mmmpizza... Member since:April 05, 2007Total points:98 (Level 1)a .50 kg mass attached to a spring undergoes simple harmonic motion with a period of .75 s what is the force constant of spring??
the answer says its 140 N/m but i cannot get that answer i am using
t=2(pi)vm/k
.75=6.28v(.15/k)
.0143=.5/k
34.9????Answer Question

Be the first to answer this question.

View the original article here

Sorry, I could not read the content fromt this page.

View the original article here

They would have to be so close that no imaginable material could be dense enough.

The basic formula is F = G Mm/ R^2
G is the universal constant of gravitation. ( = 6.67 * 10 ^ -11)
Rewriting we get R = sqrt ( G Mm/F)
= sqrt(6.67 * 10 ^ -11 * 0.47 *0.10/1.01)
=1.76 * 10 ^ -6 m.

View the original article here

Home >All Categories > Science & Mathematics >Physics >Open Question Rampriya Member since:April 20, 2010Total points:292 (Level 2)I'm curious to know whether is there any formula for that !.i thought of considering a given bar magnet as a equivalent solenoid ,and find the magnetic field at a point near by?.In case of electrostatics.it is F=eE .But in this case how can i calculate the force on the iron piece.Please help and correct me if iam wrong.thanks :)Answer Question

Be the first to answer this question.

View the original article here

Sorry, I could not read the content fromt this page.

View the original article here

Sorry, I could not read the content fromt this page.

View the original article here

View the original article here

Its a deflection, its an effect because of the way we see it.The Coriolis effect is most apparent in the path of an object moving longitudinally. On the Earth an object that moves along a north-south path, or longitudinal line, will undergo apparent deflection to the right in the Northern Hemisphere and to the left in the Southern Hemisphere. There are two reasons for this phenomenon: first, the Earth rotates eastward; and second, the tangential velocity of a point on the Earth is a function of latitude (the velocity is essentially zero at the poles and it attains a maximum value at the Equator). Thus, if a cannon were fired northward from a point on the Equator, the projectile would land to the east of its due north path. This variation would occur because the projectile was moving eastward faster at the Equator than was its target farther north. Similarly, if the weapon were fired toward the Equator from the North Pole, the projectile would again land to the right of its true path. In this case, the target area would have moved eastward before the shell reached it because of its greater eastward velocity. An exactly similar displacement occurs if the projectile is fired in any direction.

The Coriolis deflection is therefore related to the motion of the object, the motion of the Earth, and the latitude. For this reason, the magnitude of the effect is given by 2 sin , in which is the velocity of the object, is the angular velocity of the Earth, and is the latitude.

The Coriolis effect has great significance in astrophysics and stellar dynamics, in which it is a controlling factor in the directions of rotation of sunspots. It is also significant in the earth sciences, especially meteorology, physical geology, and oceanography, in that the Earth is a rotating frame of reference, and motions over the surface of the Earth are subject to acceleration from the force indicated. Thus, the Coriolis force figures prominently in studies of the dynamics of the atmosphere, in which it affects prevailing winds and the rotation of storms, and in the hydrosphere, in which it affects the rotation of the oceanic currents.

View the original article here