School and Work

A.) The index of refraction for a diamond for red light of wavelength 657 nm is 2.35, while that for blue light of wavelength 434 nm is 2.26. Suppose white light is incident on the diamond at 33.7 degree. Find the angle of refraction for red light. Answer in units of degree

B.) Find the angle of refraction for blue light. Answer in units of degree

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What is the change in enthalpy that accompanies the formation of one mole of a compound from its elements under standard conditions?

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I've never done a problem like this and do not understand.

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If your line has the equation y = 3x² + 6x - 7 then to find the x intercepts you set y = 0.

So 0 = 3x² + 6x - 7

Like you said (or implied), it won't factorize so we should use the quadratic formula to solve it.

x = [-6 +/- sqrt(6² - 4(3 x -7))] / 2(3)

x = [-6 +/- sqrt(120)] / 6

x = [-6 +/- 2sqrt(30)] / 6

x = [-3 +/- sqrt(30)] / 3

x = -1 +/- sqrt(30)/3

So those are your two answers.

x = -1 + sqrt(30)/3 or
x = -1 - sqrt(30)/3

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Sorry, I could not read the content fromt this page.

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Sorry, I could not read the content fromt this page.

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Find the length of the arc with the given y=x^3/14 bounded by x=4 and x=0 going around the x axis.

All i know is that the formula is intergral bounded by 4 and 0 aqrt[1+(dy/dx)^2]

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Home >All Categories > Science & Mathematics >Chemistry >Open Question bengalsa... Member since:September 07, 2010Total points:117 (Level 1)a 4.5g sample of NaOH at 25 C dissolves in 75ml of water also at 25 C. The final equilibrium temperature of the resulting solution is 40.5 C. What is the enthalpy of solution of NaOH expressed KJ/molAnswer Question

Be the first to answer this question.

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Home >All Categories > Science & Mathematics >Mathematics >Open Question Lala Member since:October 08, 2010Total points:395 (Level 2)the profit in dollars from the sale of x thousand compact disc players is P(x)= x^3- 3x^2+ 8x+5
find the marginal profit when the value of x is 3Answer Question

by bill Member since:March 30, 2008Total points:5,708 (Level 5)jsut take the first derivative to find marginal profit which would be
p'(x)=3x^2-6x+8+0
then set all of the x's= to 3
p'(3)=3(3)^2-6(3)+8
p'(3)=9^2-18+8
p'(3)=81-18+8
p'(3)=71

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Calculate the pOH of a 0.0827 M aqueous sodium cyanide solution at 25.0 °C. Kb for CN- is 4.49*10^(-10).

Do I use this equation?
NaCN(aq) + H2O(l) ? [Na+](aq) + [OH-](aq) + [H+](aq) + [CN-](aq)

? Kb/Kw = [Na+][CN-]/[NaCN] = x²/(0.0827 - x) = 4.49*10^4
---? x = 0.0826998 M = [Na+] = [CN-]

But then how would I get a pOH out of that? adding NaCN doesn't directly affect the concentration... or am I supposed to look up the pH of [CN-] on a table or something? I'm sorry, I really have no idea how to solve this.

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http://s303.photobucket.com/albums/nn148/imsoshyx3/?action=view¤t=graph.png

I know it's cosine but i'm not sure about the vertical translation, amplitude, or phase shift. Is the vertical translation down 1 and the amplitude 2?

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