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Home >All Categories > Science & Mathematics >Chemistry >Open Question sunbeams Member since:April 16, 2011Total points:100 (Level 1)BF3 is a pungent colourless gas (b.p. -101 degree celcius). NaF is a solid (m.p. 992 degree celcius). When BF3 reacts with NaF, it forms a compound NaBF4.
a) Describe, in terms of bonding, how NaBF4 is formed.
b) Suggest, with reasons, 2 properties of NaBF4.Answer Question

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