Open Question: Chem question: A mixture of nitrogen and oxygen are in equilibrium with nitrogen dioxide, N2 + 2O2 <--> 2NO2.?
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little Member since:September 14, 2010Total points:39 (Level 1)a. write the Keq expression
b. Calculate Keq if the concentration of N2 is [0.2 M], the concentration of O2 is [0.75M] and the concentration of NO2 is [0.5 M]Answer QuestionBe the first to answer this question.
b. Calculate Keq if the concentration of N2 is [0.2 M], the concentration of O2 is [0.75M] and the concentration of NO2 is [0.5 M]Answer QuestionBe the first to answer this question.
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Open Question: A solution contains a mixture of Cl- and Br- ions. Can both be positively identified? Write appropriate equati?
Sorry, I could not read the content fromt this page.
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Open Question: Adding 0.1M Fe(NO3)3 to a stock mixture of .01M Fe(NO3)3 and KSCN?
I did a lab last week about chemical equilibrium, and I need to explain why the stock solution of .01M Fe(NO3)3 and KSCN (which is already a rust red color) turns a darker red when 5 drops of .1M Fe(NO3)3 is added to one well (1mL stock), and why it turns even a deeper red when 5 drops of 0.1M KSCN is added to another well of the same stock (1mL). I'm thinking that it shifts everything to the right, but I can't exactly explain it? One well was the stock + 0.1M Fe(NO3) (darker red than stock), and the other well was stock + 0.1M KSCN.(even darker than when 0.1 Fe(NO3)3 was added to the other well). Why? I also need a net ionic equation to explain it... but as far as I know, it's the same reaction as the stock? Oh, everything is aqueous, btw.
Any help would be great!
Thanks!
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Open Question: You need to separate and purify a mixture of two solvents (solvent A and solvent B) in order to reclaim and?
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Reed Lalor Member since:February 10, 2011Total points:82 (Level 1)reuse them. Solvent A boils at 125 C and solvent B at 150 C. what type of distillation would you use and why? Compare the effectiveness of the distillation method you have chose with an alternative distillation.Answer QuestionBe the first to answer this question.
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