Open Question: How to find current and power in resister that's connected parallel and in series?

Open Question: How to find current and power in resister that's connected parallel and in series?

A 60.0-O resistor is connected in parallel with a 121.0-O resistor. This parallel group is connected in series with a 21.0-O resistor. The total combination is connected across a 15.0-V battery.

(a) Find the current in the 121.0-O resistor.
(b) Find the power dissipated in the 121.0-O resistor.


View the original article here

Open Question: What is the resistance of the light bulb when wired in series with 144-Ω resistor?

Open Question: What is the resistance of the light bulb when wired in series with 144-Ω resistor?

Home >All Categories > Science & Mathematics >Physics >Open QuestionHeartilly Heartill... Member since:April 21, 2011Total points:65 (Level 1)A light bulb is wired in series with a 144-O resistor, and they are connected across a 120-V source. The power delivered to the light bulb is 23.0 W. What are the two possible resistances of the light bulb?
lower value O
higher value OAnswer Question

Be the first to answer this question.


View the original article here

Open Question: Can I use the integral test for the series cos n/n?
Open Question: Is voltage and resistance shared in series circuits?

Open Question: Is voltage and resistance shared in series circuits?

Am I right in saying that for

series:
Total resistance = individual resistance of each component added
total voltage = individual voltage of each component added
current = same everywhere

parallel:
total resistance = ????????????
total voltage = same everywhere
total current = individual current of each component added

is this correct? and what is the total resistance for parallel circuits? thanks!!!!


View the original article here

Open Question: Maths problem- Geometric series?

Open Question: Maths problem- Geometric series?

ar(1+r) = 280 ......... [ I ]
ar^4(1+r) = 4375 .... [ II ]

[ II ] / [ I ]
r^3 = 4375/280 which yields
r = 2.5
substituting in [ I ] yields a = 32

ans: a = 32, r = 2.5
------


View the original article here

Open Question: Determine whether the series is convergent or divergent?

Open Question: Determine whether the series is convergent or divergent?

basically on the interval 1 to infinity the constant '9' really has no bearing because it becomes a non-factor. So the problem reduces to (k/k^2)

k/k^2 reduces to 1/k

as the limit approaches infinity you get 1/2,1/3,1/4,1/5.....1/x so you see the number is getting smaller and smaller, thus the limit approaches 0. Since the series approaches a finite number the series converges. If it went to infinity it would diverge.


View the original article here

Open Question: Taylor Series Problem?

Open Question: Taylor Series Problem?

I am having trouble how to do this:

Evaluate this limit using Taylor series:

lim x-->0 ((2cos2x - 2 + 4x^2)/2x^4) . This is 0/0 and you can use l'Hopital's rule but I am not supposed to as I am supposed to use Taylor series. Can anyone help me with a step-by-step?


View the original article here

Open Question: How do you find the power series representation for the following function?

Open Question: How do you find the power series representation for the following function?

I need to find the power series representation for the following function but I am lost, can someone please explain how one does so in this situation(step by step preferably)?

f(x)=x^2 / ( (1-2x)^2 )

Thank you for any help


View the original article here

Open Question: series n^1/n converge or diverge?

Open Question: series n^1/n converge or diverge?

Sorry, I could not read the content fromt this page.

View the original article here

Open Question: Infinite series --> converging or diverging and if converges --> find sum.?

Open Question: Infinite series --> converging or diverging and if converges --> find sum.?

Note that, by taking the limit of the n-th term as n --> infinity:
lim (n-->infinity) ln(n + 1)/ln(n^3 + 2)
= lim (n-->infinity) ln[n(1 + 1/n)]/ln[n^3(1 + 2/n^2)]
= lim (n-->infinity) [ln(n) + ln(1 + 1/n)]/[3ln(n) + ln(1 + 2/n^2)]
= lim (n-->infinity) [1 + ln(1 + 1/n)/ln(n)]/[3 + ln(1 + 2/n^2)/ln(n)]
= (1 + 0)/(3 + 0)
= 1/3.

Since this limit does not converge to zero, this series is divergent by the limit test.

I hope this helps!


View the original article here

Open Question: A series combination of a 12 k resistor and an unknown capacitor is connected to a 11 V battery.?

Open Question: A series combination of a 12 k resistor and an unknown capacitor is connected to a 11 V battery.?

Home >All Categories > Science & Mathematics >Physics >Open Questionerrca errca Member since:April 30, 2009Total points:80 (Level 1)A series combination of a 12 k resistor and an unknown capacitor is connected to a 11 V battery. One second after the circuit is completed, the voltage across the capacitor is 8 V. Determine the capacitance of the capacitor.Answer Question

Be the first to answer this question.


View the original article here

Open Question: Describe how you used a TLC plate to determine the identity of a series of unknown compounds. How does TLC?