Open Question: Calculus Integral Question?
Recall that 4^-2=1/4^2
So e^-x = 1/e^x
thus e^x^e^-x=e^x/e^x = 1
so you have integral of dx from 0 to 1 which has the anti-derivative of just x
so x evaluated at the limits is
1 - - 0 = 1
0 comentarios:
Publicar un comentario