Open Question: Calculus Integral Question?

7:52 Publicado por Flechado16

Recall that 4^-2=1/4^2

So e^-x = 1/e^x

thus e^x^e^-x=e^x/e^x = 1

so you have integral of dx from 0 to 1 which has the anti-derivative of just x

so x evaluated at the limits is
1 - - 0 = 1


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