Open Question: Factor: 6x^2-3x-18.... SHOW STEPS?

6:53 Publicado por Flechado16

Answer: (3x-6)(2x+3)

First think of two numbers thatd equal 6x^2, this being 3x and 2x. Place these numbers in their respective positions: (3x ----)(2x----)

Next think of two numbers that when multiplied equal 18. There are these options:
a) 9 x 2
b) 6 x 3
c) 18 x 1

Which of these sets of numbers that when subtracted from one another would equal 3? The answer is b) 6x3.

Thus you can plug these numbers into the factorization:
(3x-6)(2x+3)


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