Open Question: Can someone help me, i've 4 tasks, mathematic?
11:15 Publicado por Flechado16
1) log(base2)(x+2)=6-log(base2)(x+14)
2) log^x+7 -log2=log(x-5)-log8
3) log(base3) (2*3 exponent3 -1)= -1
4) log (X on squared + X - 2) = 1
5) log x + log(x-3)
--------------- = 2
log( -x+6)
6) log(x+3) + log(x-3)=log7
7) log(base x+2) (5x+6)=2
7 de noviembre de 2011, 0:18
I think you should first try it yourself .It may be you don't get good guidance .I am giving you some rules to solve logarithms.Firstly try to solve it .
Laws of Natural Logarithms:-
Below are the laws of natural logarithms -
The exponential equation,
x = ey
To find the natural logarithm by taking the base e logarithm of both sides of the above exponential equation.
x = ey
loge(x) = loge(ey)
loge(x) = y or ln x = y [ Because loge(e) cancels, the equation becomes ]
The following laws help in solving natural logarithms : [here, ln x = logex]
ln (x × y) = (ln x) + (ln y). (Product rule)
ln (x / y) = (ln x) - (ln y) (Quotient rule)
ln (xn) = (n) ln x (Power rule)
Try to use these rules .Then also you will not able to solve it .I will definitely help you or if it's urgent for you then visit tutorvista.com for these type of problems such as logarithms, algebra and statistics
ln x = 1 / logxe where x represents any numbers. (Reciprocal rule)