Open Question: A compact car, mass 755 kg, is moving at 1.00 multiplied by 102 km/h toward the east?
I think you are meaning 10^2 and 10 ^ 3 in the question.
If so the speed of the car is 100 Km/hr which is quite plausible.
If so the speed of the car is 100 Km/hr which is quite plausible.
We need to convert Km/hr to m/s so must multiply by 1000 m/km and divide by 3600 secs / hr
so speed = 100/3.6 = 27.8 m/s
Its initial momentum was MV = 755 * 27.8 = 2.1 * 10 ^4 Ns
During braking an amount of impulse = FT = 2.5 * 5.2 * 10^3 = 1.3 * 10 ^ 4 Ns has been lost.
So the final momentum is initial - lost
= 2.1 * 10 ^ 4 - 1.3 * 10 ^ 4 = 7990 Ns
Now once more momentum = MV
so 7990 = 755 * V
V = 7990 / 755 = 10.6 m/s ( about 37 Km/hr)
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