Open Question: Having trouble with this integral..?
? (2dx)/((x^2)+1) = 2 ? (dx)/((x^2)+1)
= 2(arctanx) from 1 to infinity
= 2(pi/2 - pi/4) = pi/2.
= 2(arctanx) from 1 to infinity
= 2(pi/2 - pi/4) = pi/2.
Since, arctan(infinity) = pi/2
and arctan(1) = x
tan(x) = 1 --> x = pi/4.
0 comentarios:
Publicar un comentario