Open Question: How do I find the integral of x-x^-2 / 2x^-1+x^2?
4:00 Publicado por Flechado16
Let u = x^2 + 2x^-1; then du = (2x - 2x^-2) dx, or (x - x^-2) dx = 1/2 du.
The integral becomes: (1/2)(integral) du/u = (1/2)ln(x^2 + 2x^-1) + C
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