i = v-1
i² = -1

* * * *

In terms of i, we obtain:

3d² - 17(i²) = 0

You can factor that expression by differences of squares a² - b² = (a - b)(a + b), letting a = v(3d²) = dv3 and b = iv(17).

(dv(3) + iv17)(dv(3) - iv17) = 0

Therefore, by zero-product identity

dv(3) + iv(17) = 0 and dv(3) - iv(17) = 0
d = ±iv(17/3)

I hope this helps!

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