Open Question: how to integrate x^2/(1+x^2)?
Re write the top ,i.e., x^2 as x^2+1-1
hence x^2/(1+x^2) = (x^2+1)/(1+x^2) - 1/(1+x^2) = 1 - 1/(1+x^2)
Hence the integral answer is x - arctan(x) +C
hence x^2/(1+x^2) = (x^2+1)/(1+x^2) - 1/(1+x^2) = 1 - 1/(1+x^2)
Hence the integral answer is x - arctan(x) +C
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