Open Question: A voltaic cell consists of Mn/Mn2+ and Pb/Pb2+ half cells. Calculate the concentration of Pb2+ given......?

A voltaic cell consists of Mn/Mn2+ and Pb/Pb2+ half cells. Calculate the concentration of Pb2+ when the concentration of Mn2+ is 1 M and Ecell is 0.44V.

Please help. I believe you use the equation Ecell = standard-Ecell - ( 0.0592V / n) (log Q), but I cannot get the right answer.

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