Let's take one part of it

5^(1/3) (the cubed root of 5)

x^3 - 5 is the polynomial with a root of 5^(1/3) therefore 5^(1/3) is an algebraic number

That's the hard bit done for you :) What you need is a polynomial which has the root of your equation

x^3-3 x^2+3 x-6 easy

View the original article here