Open Question: Calculate the Jacobian from the spherical to the cartesian coordinate?

5:41 Publicado por Anónimo

The way we read this question is that you go from spherical coordinates: p, theta, phi to cartesian x y z

r= sqrt(x2 + y2 + z2)
theta= arctan(y/x)
phi= arccos(z/r)

I can do the partial derivatives of r and theta, but phi is getting too complex.

This makes me wonder, are we reading the question correctly? and if so can someone work and show the work of the 3 partial derivatives of phi? I can do the matrix of the 9 partial dervs


View the original article here

  • Digg
  • del.icio.us
  • StumbleUpon
  • Yahoo! Buzz
  • Technorati
  • Facebook
  • TwitThis
  • MySpace
  • LinkedIn
  • Live
  • Google
  • Reddit
  • Sphinn
  • Propeller
  • Slashdot
  • Netvibes

0 comentarios:

Publicar un comentario