Open Question: I fire a cannon with muzzle velocity 120m/s at an angle of 45 degrees. (Projectile Motion)?
10:47 Publicado por Nadim
Since it is at a 45 degree angle, the horizontal and vertical components of vel are equal, so vx=vy=120/sqrt(2)
now plug it in h0=h+vit+.5at^2
0=-(120/sqrt(2))t-4.9t^2 and solve for t
t ends up being 120/(sqrt(2)*4.9) (plug it in a calc to find the actual number)
just multiply this number by the hx velocity, and you will get 120/4.9! (or close to 24 meters)
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