Open Question: Verify the identity: cos^2x-sin^2x=1-2sin^2x, what are the steps?
Pythagorean Identity
sin^2(x) + cos^2(x) = 1
or
cos^2(x) = 1 - sin^2(x)
sin^2(x) + cos^2(x) = 1
or
cos^2(x) = 1 - sin^2(x)
substitute it into the left hand side
1 - sin^2(x) - sin^2(x) = 1 - 2sin^2(x)
Now LHS = RHS
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