School and Work

Use a graph and the Location Principle to find the real zeros of:

P(x) = 2x^3 - 4x + 1

1) (-1.3, 0.3, -1.5)
2) (1.3, -0.3, 1.5)
3) (-1.3, -0.3, 1.5)
4) (1.3, 0.3, 1.5)
5) (1.3, 0.3, -1.5)

View the original article here

y intercept when x = 0

so for 1.)

f(0) = 3^0 + 1
f(0) = 2 ? y intercept.

domain is all real numbers, x can be any negative number as well, eg 3^(-1) + 1 = 4/3

so on the graph for coordinate -1 the corresponding y value is 4/3.

etc, and as you input x as x ? -infinity you get the asymptote, which is 3^-99999 + 1,

and if you put x ? infinity you get the other asymptote

View the original article here

Sorry, I could not read the content fromt this page.

View the original article here

so i need this on an assignment for school and i wasn't really listening when he explained it. I just want the 3 components in paragraph form. :P oh and dont add to many sophisticated words because im copy and pasting.

heres the question word for word: describe the 3 major components necessary to help you understand the relationship between a graph, equation and a table of values.

View the original article here

Sorry, I could not read the content fromt this page.

View the original article here

F(x)=-(x-5)^3
F'(x) = -3(x-5)^2
F''(x) = (-3)(2)(x-5)
F''(x) = -6(x-5)=0

x=5 is a point of inflection

Test for concavity:
Consider the intervals (-8 ,5), (5, 8)

choose any one point from each of the intervals.
if F''(x) < 0 , F(x) is concave down on that interval
if F''(x) > 0 , F(x) is concave up on that interval

F''(x)= -6(x-5)
(-8 ,5): choose x=1; F''(1)=24 > 0, f is concave up on (-8 ,5):
(5, 8): choose x=6; F''(1)=-6 < 0, f is concave down on (5, 8):

F is concave up on (-8 ,5):

View the original article here

You defined x= 0 at the year 1920.

Therefore, you have the equation:

y= -.02x + (y-intercept)

If you plug in the values for 1920, you get:
46.6= -.02(0) + (y intercept)

The y-intercept is 46.6.

This also works if you plug in x= 60 years and 45.4 seconds.

So no, your answer is not correct. Sorry :(

View the original article here

3. y = tan (x- (pie/3))
Answer: period = (pie), Vertical Asymptoes x= -(pie)/6 x = 3(pie)/6

I cant find the points in between......

4. Y= csc(2x-(pie))

View the original article here

Home >All Categories > Science & Mathematics >Mathematics >Open Question woopsie Member since:January 08, 2009Total points:107 (Level 1)g(x) = -3sin2(x - pi/8) + 1
a. Determine the period of the curve.
b. The curve g(x) can be obtained by reflecting the curve f(x) = a sin bx into the x – axis and
then translating with the vector translation (p, q). Find the values of a, b, p and q.Answer Question

Be the first to answer this question.

View the original article here

Sorry, I could not read the content fromt this page.

View the original article here

http://s303.photobucket.com/albums/nn148/imsoshyx3/?action=view¤t=graph.png

I know it's cosine but i'm not sure about the vertical translation, amplitude, or phase shift. Is the vertical translation down 1 and the amplitude 2?

View the original article here