Open Question: differentiate sin((x^3)-4)^5?

13:08 Publicado por Nadim

y = [ sin ( x ³ - 4 ) ]^5

dy/dx = 5 [ sin ( x ³ - 4 ) ]^4 [ cos ( x ³ - 4 ) ] [ 3 x ² ]

dy/dx = 15 x ² [ sin ( x ³ - 4 ) ]^4 [ cos ( x ³ - 4 ) ]


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