Open Question: arrange the bonds in order of increasing polarity? I-F, Br-F, Br-Br?
I-F is first - All you need to do is look at electronegativity for polarity
I is less electronegative than Br so it does not pull the electron density as much as bromine would.
Because F is the most electronegative, more electron density is towards the F when the other atom is less electronegative
And Br-Br is last because the electron density is shared equally
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