If someone could show me how to solve this it would be greatly appreciated. i have found the weight, normal force, parallel force, etc. but i have no clue what else to do. thanks

A 3050 kg roller coaster is at the base of the first hill when the chain lift grabs it and begins pulling it up the slope. The angle of the incline is 38.7o, and the coefficient of roller coasting friction is 0.205. If the height of the first hill is 33.0 m and it took the roller coaster 55.4 s to reach the top,
a) how much force is applied by the chain lift to pull the roller coaster to the top of the hill?

b) how much work was done by the chain lift?

c) what was the power exerted by the chain lift?

d) what was the potential energy of the coaster at the top of the hill?

e) why was the work done greater than the potential energy gained?

f) Neglecting friction on the way down, what would be the speed of the roller coaster at the bottom of the hill on the other side?

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