Open Question: a 15.4 g ice cube is placed into 316 g of water. calculate the temperature change in the water upon complete?
7:56 Publicado por Flechado16
(15.4 g / 18.0 g/mol) times 6.02 kJ/mol = 5.15 kJ = 5150 J
5150 J = (316 g) (?t) (4.184 J/g C)
?t = 3.90 C
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