Open Question: Calculus: Find an equation of the tangent line to the curve at the given point?
6:00 Publicado por Flechado16
f(x) = (1 + 2x)¹° so f '(x) = 10(1 + 2x)? •2 = 20(1 + 2x)?
Since the point is (0,1) the slope at that point is f '(0) = 20(1)? = 20
So using the point-slope form of the line
y – 1 = 20(x – 0) or y = 20x + 1
0 comentarios:
Publicar un comentario