Open Question: Integrate this integral ?
16:20 Publicado por Flechado16
Let x^4 = u
4 x^3 dx = du
x^3 dx = (1/4) du
4 x^3 dx = du
x^3 dx = (1/4) du
Integral x^3e^x^4 dx = (1/4) integral e^u du
= e^u / 4 + C
= e^x^4 / 4 + C
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