Open Question: Natural logarithm problem help?
11:29 Publicado por Flechado16
v2 = 2^(½), and ½ = 2^(-1), so by rules of logs,
- ln 1/v2 = · · · · · · · power rule
ln (1/v2)^(-1) =
ln v2 =
ln 2^(½) = · · · · · · · power rule again
½ ln 2
0 comentarios:
Publicar un comentario