Open Question: Simplifying expressions? index 4√x^2 minus sign index 4√x^6 divided by x (the x^2 and the x^6 are inside √)?
23:08 Publicado por Flechado16
Note that "index 4vx^2" = x^(2/4) = x^(½). "index 4vx^6" follows that scenario.
(x^(2/4) - x^(6/4))/x
==> (x^(½) - x^(3/2))/x
Finally, by an/a^b = a^(n - b)..
x^(½ - 1) - x^(3/2 - 1)
==> x^(½ - 2/2) - x^(3/2 - 2/2)
==> x^(-½) - x^(½)
==> 1/x^(½) - x^(½)
==> (1/vx) - vx
I hope this helps!
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