School and Work

Note that "index 4vx^2" = x^(2/4) = x^(½). "index 4vx^6" follows that scenario.

(x^(2/4) - x^(6/4))/x
==> (x^(½) - x^(3/2))/x

Finally, by an/a^b = a^(n - b)..

x^(½ - 1) - x^(3/2 - 1)
==> x^(½ - 2/2) - x^(3/2 - 2/2)
==> x^(-½) - x^(½)
==> 1/x^(½) - x^(½)
==> (1/vx) - vx

I hope this helps!

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Home >All Categories > Science & Mathematics >Mathematics >Open Question crystalq... Member since:May 05, 2007Total points:691 (Level 2)Show me each step please because I have never worked such a problem. I would appreciate your assistance with the work so that I can learn and do the rest of the similar problems. Thank you! The first person with the best answer will get the points! :)Answer Question

by Charles Member since:March 11, 2011Total points:493 (Level 2)Take root both side you will get
(x plus.minus root 12 ) = plus.Minus root 10
now you have 4 cases that
1. + +
2. + -
3. - -
4. - +
answers are
1. Root 10- root12
2. -Root 10- root12
3. -Root 10 +root12
4. Root 10 + root12

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