Open Question: Where do I use the K of Cu(NH3)4 in this problem?
Calculate the molar solubility of Cu(OH)2, Ksp = 2.2 × 10–20, in 0.32 M NH3, in mol/L. Don't forget to use the complexation reaction Cu2+ + 4 NH3 ? Cu(NH3)42+, K = 5.0 × 1013.
I thought I just had to find x, the extra information is throwing me off.
0 comentarios:
Publicar un comentario