Open Question: Where do I use the K of Cu(NH3)4 in this problem?

5:04 Publicado por Flechado16

Calculate the molar solubility of Cu(OH)2, Ksp = 2.2 × 10–20, in 0.32 M NH3, in mol/L. Don't forget to use the complexation reaction Cu2+ + 4 NH3 ? Cu(NH3)42+, K = 5.0 × 1013.

I thought I just had to find x, the extra information is throwing me off.


View the original article here

  • Digg
  • del.icio.us
  • StumbleUpon
  • Yahoo! Buzz
  • Technorati
  • Facebook
  • TwitThis
  • MySpace
  • LinkedIn
  • Live
  • Google
  • Reddit
  • Sphinn
  • Propeller
  • Slashdot
  • Netvibes

0 comentarios:

Publicar un comentario