If you're really wanting to know how to do this problem, then don't give us multiple choice answers. Simple as that.

The real way to find this is to figure out the probability that 0 or 1 eggs are broken, then subtract that from 100%.

The probability that 0 eggs are broken is (0.98)^12 because each individual egg has a 98% chance of staying intact, and the probabilities of those are each independent of one another. The probability that a single egg is broken is (0.02)*(0.98)^11, but there are 12 possibilities of those, so you have to multiply that number by 12.

(0.98)^12 + 12(0.02)(0.98)^11
0.7847 + 0.1921
0.9768 or 97.68%. That's the probability that exactly 0 or 1 eggs are broken. To find 2 more eggs:
1 - 0.9768 (that's 100% - 97.68%)
That will give you 0.0232 or 2.3 %. (NOT 0.2%)

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