Open Question: How do I find the X value in a equation like 4LN(4X-2)+4=0 ?
3:24 Publicado por Anónimo
4 ln (4x - 2) + 4 = 0
4 ln (4x - 2) = - 4
ln (4x - 2) = - 1
in exponential form...
(4x - 2) = 1/e
4x = 2 + (1/e) = (2e + 1)/e
x = (2e + 1)/(4e)
check...read your textbook...practice...
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