Open Question: Integration of (x+1)^3/x dx- help please!?
Let's just work with the function:
(x+1)^3/x = (x^3 + 3x^2 + 3x + 1)/x = x^2 + 3x + 3 + (1/x)
now it should be easy to integrate term-wise.
(x+1)^3/x = (x^3 + 3x^2 + 3x + 1)/x = x^2 + 3x + 3 + (1/x)
now it should be easy to integrate term-wise.
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