Open Question: I'd really just like someone to check this answer?

14:29 Publicado por Nadim

(x^2*y/2y^2)(4y^4/x^3)

that is the original problem. here is how I solved it. I reduced the x values, taking the x out of the numerator and leaving one x in the denomenator. Then I factored the y values. Taking away the y in the denomenator and leaving y^2 in the numerator. then I mutiplied what I had gotten from factoring, which was (1y/2)(4y^2/1x). That gave me (4y^3/2x) which I reduced to (2y^3/x). Does that sound right?


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