Open Question: Solve for y: 3^(2y-1) = 99?
20:09 Publicado por Nadim
Take logs
(2*y - 1)*log(3) = log(99)
2*y - 1 = log(99)/log(3)
2*y = 1+ (log(99)/log(3))
y = (1/2)*(1+ (log(99)/log(3)))
Over to you and your calculator!
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